/* Author: Pate Williams (c) 1998 3.34 Algorithm Finding square roots modulo a prime. See "Handbook of Applied Cryptography" by Alfred J. Menezes et al page 100. */ #include #include int JACOBI(long a, long n) { int s; long a1, b = a, e = 0, m, n1; if (a == 0) return 0; if (a == 1) return 1; while ((b & 1) == 0) b >>= 1, e++; a1 = b; m = n % 8; if (!(e & 1)) s = 1; else if (m == 1 || m == 7) s = + 1; else if (m == 3 || m == 5) s = - 1; if (n % 4 == 3 && a1 % 4 == 3) s = - s; if (a1 != 1) n1 = n % a1; else n1 = 1; return s * JACOBI(n1, a1); } void extended_euclid(long a, long b, long *x, long *y, long *d) /* calculates a * *x + b * *y = gcd(a, b) = *d */ { long q, r, x1, x2, y1, y2; if (b == 0) { *d = a, *x = 1, *y = 0; return; } x2 = 1, x1 = 0, y2 = 0, y1 = 1; #ifdef DEBUG printf("------------------------------"); printf("-------------------\n"); printf("q r x y a b "); printf("x2 x1 y2 y1\n"); printf("------------------------------"); printf("-------------------\n"); #endif while (b > 0) { q = a / b, r = a - q * b; *x = x2 - q * x1, *y = y2 - q * y1; a = b, b = r; x2 = x1, x1 = *x, y2 = y1, y1 = *y; #ifdef DEBUG printf("%4ld %4ld %4ld %4ld ", q, r, *x, *y); printf("%4ld %4ld %4ld %4ld ", a, b, x2, x1); printf("%4ld %4ld\n", y2, y1); #endif } *d = a, *x = x2, *y = y2; #ifdef DEBUG printf("------------------------------"); printf("-------------------\n"); #endif } long inverse(long a, long b) /* returns the inverse of a modulo b if it exists 0 otherwise */ { long d, x, y; extended_euclid(a, b, &x, &y, &d); if (d == 1) return x; return 0; } long exp_mod(long x, long b, long n) /* returns x ^ b mod n */ { long a = 1, s = x; while (b != 0) { if (b & 1) a = (a * s) % n; b >>= 1; if (b != 0) s = (s * s) % n; } return a; } long square_root_mod(long a, long p) /* returns the square root of a modulo an odd prime p if it exists 0 otherwise */ { long ai, b, c, d, e, i, r, s = 0, t = p - 1; /* is a quadratic nonresidue */ if (JACOBI(a, p) == - 1) return 0; /* find quadratic nonresidue */ do do b = rand() % p; while (b == 0); while (JACOBI(b, p) != - 1); /* write p - 1 = 2 ^ s * t for odd t */ while (!(t & 1)) s++, t >>= 1; ai = inverse(a, p); c = exp_mod(b, t, p); r = exp_mod(a, (t + 1) / 2, p); for (i = 1; i < s; i++) { e = exp_mod(2, s - i - 1, p); d = exp_mod((r * r % p) * ai % p, e, p); if (d == p - 1) r = r * c % p; c = c * c % p; } return r; } int main(void) { long a, p; printf("x ^ 2 = a mod p\n"); for (;;) { printf("a or 0 to quit = "); scanf("%ld", &a); if (a == 0) break; printf("p = "); scanf("%ld", &p); printf("square_root_mod(%ld, %ld) = %ld\n", a, p, square_root_mod(a, p)); } return 0; }